Two particles of equal mass ‘m’ go around a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle with respect to their center of mass is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
= m ω 2 R
= ω 2
ω = 
⇒ v = ω R
v = 
× R = 
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